convert an array into individual strings

I have the following arrays and I would like to convert each one of them into individual strings. In other words, break the array into individual pieces.

  $formatsArray = $_POST['formats'];
      $topicsArray = $_POST['topics'];

This is because I would like to include the individual strings in the following query "

  $resources = "select * from resources where
                    stage LIKE '%".$stage."%'
                    AND format LIKE '%".$formats."%'";


      $run_query = mysqli_query($con, $resources);

This is because format expect an individual string for comparison, such as lets assume the array is ["video", "blogs", "articles"], it wouldn't work if format was to be compared with video,blogs,articles but rather video, blogs or articles.

I hope this is clear, and for any clarification, please advise.

All the best,

Update:

$formats = explode(',', $formatsArray);
      $topics = explode(',', $topicsArray);


      $resources = "select * from resources where
                    stage LIKE '%".$stage."%'
                    AND format LIKE '%".$formats."%' AND topic LIKE '%".$topics."%' ";

update:

$run_query = mysqli_query($con, $resources);


  while($row = mysqli_fetch_array($run_query)) {

    $data[] = array(
      'format' => $row['format'],
      'title' => $row['title'],
      'costs' => $row['cost'],
      'stage' => $row['stage'],
      'topic' => $row['topic'],
      'link' => $row['link']
    );
  }




Answer:




Ignoring the necessity of prepared statements, you could do:

  $formats = implode('","', $formatsArray);
  $topics = implode('","', $topicsArray);

  $resources = "select * from resources where
                stage LIKE '%".$stage."%'
                AND format IN(".$formats.") AND topic IN(\"".$topics."\") ";

By adding the " before and after each , when you implode each array, your array would become e.g.

video","blogs","articles

So, we need to add the " to the beginning and end of each IN list. This will make the final query like:

select * from resources where
stage LIKE '%".$stage."%'
AND format IN("video","blogs","articles") AND ...


Answer:



I think this would do it. This also will resolve the injection hole by using prepared statements.

$query = 'select * from resources where ';
if(!empty($_POST['formats'])){ 
foreach($_POST['formats'] as $key => $format) {
    $query .= 'stage LIKE :stage' . $key . ' or ';
    $execute[':stage' . $key] = '%' . trim($format) . '%';
}
}
if(!empty($_POST['topics'])){
foreach($_POST['topics'] as $key => $topic) {
    $query .= 'topic LIKE :topic' . $key . ' or ';
    $execute[':topic' . $key] = '%' . trim($topic)  . '%';
}
}
$query = rtrim($query, ' or ');
if(!empty($execute)) {
    echo $query;
    print_r($execute);
    //$stmt = $mysqli->prepare($query);
    //$stmt->execute($execute);
} else {
    echo 'You must search for something';
}

Gives you a query of

select * from resources where stage LIKE :stage0 or stage LIKE :stage1 or topic LIKE :topic0 or topic LIKE :topic1 or topic LIKE :topic2 or topic LIKE :topic3

and bound values of:

Array
(
    [:stage0] => %test%
    [:stage1] => %test1%
    [:topic0] => %value1%
    [:topic1] => %value2%
    [:topic2] => %value3%
    [:topic3] => %value4%
)

Here's the initial code I had for when I thought the data was paired..

foreach($formats as $key => $format) {
    $topic = $topics[$key];
    $query .= '(stage LIKE :stage' . $key . ' and topic LIKE :topic' . $key . ') or ';
    $execute[':stage' . $key] = '%' . trim($format) . '%';
    $execute[':topic' . $key] = '%' . trim($topic)  . '%';
}

A few links on prepared statements:
http://php.net/manual/en/mysqli.quickstart.prepared-statements.php
http://php.net/manual/en/mysqli.prepare.php
http://php.net/manual/en/mysqli-stmt.execute.php