PHP Tutorial - Replacing letters simultaneously with strtr

I'm trying to replace a string simultaneously with strtr but I came across a problem. If the letter being replaced simultaneously is next to another letter that is being replaced simultaneously it doesn't replace the letter after the first letter. What can I do to fix this? Thanks.

$text = " no bacon cats nobody ";
$text = strtr($text, array(" no " => " bacon ", " bacon " => " no ", " cats " => " dogs "));
echo $text;

Expected Results

bacon no dogs nobody

Actual Results

bacon bacon dogs nobody

P.S: I have to make sure those words aren't part of another word. That's why the white spaces are there. For example, the word "no" is part of "nobody", and if you replaced all "no" in the string, it would also replace words like "nobody";

Answer:

So what happens here?

$text = " a b c ";
$text = strtr($text, array(" a " => " b ", " b " => " a ", " c " => " d "));

First you have to know that:

1. The longest keys will be replaced first
2. After it got replaced it doesn't search for this key anymore

So here all keys have the same length, means it will replace the first key => value element, then the second and so on.

So first " a " => " b " will be replaced, which will change your start string:

 a b c 
↑↑↑ Match

to this:

 b b c
↑↑↑ Replacement

Remember how we said, after replacing the values it doesn't search for it anymore? Exactly! Now it searches for " b " => " a ", but only in this part of the string:

 a b c 

So it won't find it, since there is no space in front of the b to search for. That's why you don't get your expected output. And c will be found again, since it has a space in front of it.

So the problem here in your code is, that it doesn't include replaced values in the search of the next key. Even if [space]b[space] is in your string, it doesn't find it, since the first space is from the replaced value of the key [space]a[space], which won't be included in the next search.

EDIT:

As from your updated question it seems that you have done this to try to prevent words be part of other words. To solve this simply make a lookup array and use preg_replace_callback() with word boundarys to match only full words and not only a part of it, e.g.

<?php

    $text = " apple bacon cats ";
    $replacement = ["apple" => "bacon", "bacon" => "apple", "cats" => "dogs"];
    echo $text = preg_replace_callback("/\b(" . implode("|", array_keys($replacement)) . ")\b/", function($m)use($replacement){
        return $replacement[$m[1]];
    }, $text);

?>




Answer:

A way without strtr:

$text = 'no bacon cats nobody';
$rep = ['no'=>'bacon', 'bacon'=>'no', 'cats'=>'dogs'];

$parts = explode(' ', $text);
foreach ($parts as &$part) {
    if (isset($rep[$part]))
        $part = $rep[$part];
}

$result = implode(' ', $parts);

if you want something more flexible, replace the explode line with:

$parts = preg_split('~\b~', $parts);

and use an empty string with implode.

Answer:

Don't include white space around the words you're searching for in your strings. It's causing PHP to not find some of the characters it's supposed to replace. Remember, PHP thinks of white space as characters too, so "bacon " != " bacon ".

Like this:

<?php

$text = " apple bacon cats ";
$text = strtr($text, array("apple" => "bacon", "bacon" => "apple", "cats" => "dogs"));
echo $text;
echo $text; // outputs " bacon apple dogs "

?>